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Alternatively, one can use an integral estimate:sum_{n=2}^{k} (1/n^2) \leq int_{1}^{k} (1/x^2) dx =1-1/k < 2/3 for k \geq 2.
Alternatively, one can use an integral estimate:
ReplyDeletesum_{n=2}^{k} (1/n^2) \leq int_{1}^{k} (1/x^2) dx =1-1/k < 2/3 for k \geq 2.