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If x is a root of P and P(P(P(x))): P(x)=0 P(P(x))=c P(P(P(x)))=c^2+bc+c=c(c+b+1)=0We can easily see that P(0)=c, P(1)=1+b+c and rewrite this as: P(0)P(1)=0
If x is a root of P and P(P(P(x))):
ReplyDeleteP(x)=0
P(P(x))=c
P(P(P(x)))=c^2+bc+c=c(c+b+1)=0
We can easily see that P(0)=c, P(1)=1+b+c and rewrite this as:
P(0)P(1)=0