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Wednesday, February 17, 2016

Advanced Knowledge Problem of the Week

Don't miss this week's Advanced Knowledge Problem of the Week, which asks you to take a different angle on some trigonometric functions.


You can see my solution below the break.
Solution video:


Solution transcript:


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1 comment:

  1. Kevin WeatherwalksFebruary 17, 2016 at 11:22 PM

    factor out a cos(x) to get:
    cosx*(tanx + 1)*(tanx + cotx)
    =cosx*(tan^2x + 1 + tanx + cotx)
    =cosx*(sec^2x + (sin^2x + cos^2x)/(sinx*cosx)) [1]
    = secx + cscx

    [1] since a/b + b/a = (a^2 + b^2)/(a*b) and tan^2x + 1 = sec^2x

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