Take a look after the break to find out just how many man-hours are wasted by this confluence of laziness and bureaucracy.
If you can figure out an efficient way to find what the necessary adjustment is to the expected number of people who get summonsed twice, or if you've just found another cool way of solving the problem, let us know in the comments!
As n (=780) is 'large' and p (=1/2500) is 'small', a Poisson approximation with mean np (=0.312) gives the same answer.
ReplyDeleteI read the question differently. It says, "what's the probability that a resident..." I interpreted this to mean, "any resident" where you interpreted it to mean, "a particular resident."
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