tag:blogger.com,1999:blog-5159574672638793285.post1825051723917180599..comments2024-01-29T06:01:15.858-05:00Comments on The Center of Math Blog: Problem of the Week: 4-4-17Center of Mathematicshttp://www.blogger.com/profile/06584574038886207370noreply@blogger.comBlogger1125tag:blogger.com,1999:blog-5159574672638793285.post-43338883046805890282017-04-05T04:29:51.915-04:002017-04-05T04:29:51.915-04:00Another solution is to solve $x^n=x^(n-1)+2*x^(n-2...Another solution is to solve $x^n=x^(n-1)+2*x^(n-2)$. The roots of the equation are -1, 0 and 2 that means the solution can be found in the form $a_n = c*(-1)^n+d*0^n+e*2^n$. Using a_1 = 1, a_2 = 8 and 0^n=0 it is easy to find koefficientsAnonymoushttps://www.blogger.com/profile/16297250183368083798noreply@blogger.com